3x(x^2-16)-x^2=4/3x(6+9x)

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Solution for 3x(x^2-16)-x^2=4/3x(6+9x) equation: 



3x(x^2-16)-x^2=4/3x(6+9x)

We move all terms to the left:

3x(x^2-16)-x^2-(4/3x(6+9x))=0



Domain of the equation: 3x(6+9x))!=0

x∈R



We add all the numbers together, and all the variables

-x^2+3x(x^2-16)-(4/3x(9x+6))=0

We add all the numbers together, and all the variables

-1x^2+3x(x^2-16)-(4/3x(9x+6))=0

We multiply parentheses

-1x^2+3x^3-48x-(4/3x(9x+6))=0

We multiply all the terms by the denominator


-1x^2*3x(9x+6))+3x^3*3x(9x+6))-48x*3x(9x+6))-(4=0

We do not support expression: x^3

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